If the coefficient of kinetic friction between the player and the ground is 0.48, how far does the player slide before coming to rest?
1 Answer

you will need to combine two equations
the first is
vf^2 = v0^2 + 2 a d
vf = final velocity = 0
v0=initial velocity = 4.4 m/s
a = accel which we will have to find
d = distance which is the ultimate answer we want
we need to find the acceleration, which we obtain from
net force on the player = m a
in this case, the force is due to friction which is given by f = u m g where u is the coeff of friction
so since F = m a = u m g we have that a = u g
find the value of a from a = 0.48*9.8m/s/s
substitute this into the first equation and solve for d
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