# A cyclist accelerates from rest at a rate of 1.00 m/s2. How fast will a point on the rim of the tire?

A cyclist accelerates from rest at a rate of 1.00 m/s2. How fast will a point on the rim of the tire (diameter = 68 cm) at the top be moving after 1.1 s? (Hint: At any moment, the lowest point on the tire is in contact with the ground and is at rest.

Can someone please show me how his is done? i have no idea what i am doing? thanks

• okay there are quite a few steps to this problem.

The equation that will solve this problem is v=2*r*w

There are steps that we need to find these.

1. to find r we will divide the diameter 68 cm by 2 to get the radius

68cm/2= 34cm

2. to find omega (w) we will use the formula w=wi+alpha*t

we need to use this formula to find alpha: alpha=a/r

alpha is 1/34.

so just plug into the formula w=wi+alpha*t

=0+(1/34)(1.1)

w =0.0323529412

so to solve the whole problem is the formula v=2*r*w

v=2*34*0.0323529412

=2.2 m/s

I hope this helps if you....

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