A cyclist accelerates from rest at a rate of 1.00 m/s2. How fast will a point on the rim of the tire (diameter = 68 cm) at the top be moving after 1.1 s? (Hint: At any moment, the lowest point on the tire is in contact with the ground and is at rest.
Can someone please show me how his is done? i have no idea what i am doing? thanks
1 Answer

okay there are quite a few steps to this problem.
The equation that will solve this problem is v=2*r*w
There are steps that we need to find these.
1. to find r we will divide the diameter 68 cm by 2 to get the radius
68cm/2= 34cm
2. to find omega (w) we will use the formula w=wi+alpha*t
we need to use this formula to find alpha: alpha=a/r
alpha is 1/34.
so just plug into the formula w=wi+alpha*t
=0+(1/34)(1.1)
w =0.0323529412
so to solve the whole problem is the formula v=2*r*w
v=2*34*0.0323529412
=2.2 m/s
I hope this helps if you....