A gas is at 20°C. To what temperature must it be raised to triple the rms speed of its molecules?

Can someone help me, I don’t understand this exercise. Its give another answer. Something like 6.6443×10^-27, too low. But the real answer is 2364oC

1 Answer

  • Formula for RMS velocity(C) is

    C=sq.rt(3RT/M)

    So, C directly proportional to T in kelvin(273+20=293)

    So, C1/C2=T1/T2

    C2=C1XT2/T1

    3C1=C1XT2/T1

    3=T2/T1

    T2=3XT1

    T2=3×293

    T2=2637k=(2637-273)=2364oC

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