A hand exerciser utilizes a coiled spring?

A force of 89.0 N is required to compress the spring by 0.0191 m. Determine the force needed to compress the spring by 0.0508 m.

3 Answers

  • F = kx

    89.0 N = k * 0.0191 m

    k = 89.0 / 0.0191 = 4660 N/m

    Force to compress the spring by 0.0508 m = kx = 4660 N/m * 0.0508 N/M = 236.7 N

  • First, find the spring constant: F = k × x (88.3 N) = k × (0.0183 m) k = 4825 N/m Now find the force needed: F = k × x F = (4825 N/m) × (0.0471 m) F = 227 N

  • = (89/.0191)*.0508= 236.712 N

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