a rigid tank whose volume is unknown is divided into two parts by a partition. THERMODYNAMICS HELP!!!!?

One side of the tank contains an ideal gas at 927 degrees Celsius. The other side is evacuated and has a volume twice the size of the part containing the gas. The partitions is now removed and the gas expands to fill the entire tank. Heat is now applied to the gas until the pressure equals the initial pressure. Determine the final temperature of the gas. Please help i dont know what to do at all=/

• Ti = 927 deg. C = 1200 K

Vf = 3*Vi

Pi = P

Pf = P

Using gas ideal equation,

PiVi/Ti = PfVf/Tf, Pi = Pf

Vf/Ti = Vf/Tf

Tf = Ti*(Vf/Vi)

Tf = 1200*(3)

Tf =3600 K = 3327 deg. C

• i dont comprehend if u are acquainted with 2d grade equations so im providing a a lot less complicated answer merely divide 1512 into factors: 1512=2x2x2x3x3x3x7 now, u ought to multiply a number of them and something else as a thanks to get the sum seventy 8 social gathering; attempt 2x2x2x3=24 and the last 3x3x7=sixty 3 and u dont get seventy 8 besides, after some tries u will locate 2x2x3x3=36 and the last 2x3x7=40 2 which have the sum seventy 8 so the nrs are 40 2 and 36 this problem is unquestionably solved with 2d grade equations" enable the first nr be x and the 2d be seventy 8-x u have x*(seventy 8-x)=1512 78x-x^2-1512=0 or x^2-78x+1512=0. then u keep on with the formulation, if u comprehend it

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