A scuba diver’s tank contains 0.29kg of O2 compressed into of 2.3L,?

a) calculate the gas pressure inside the tank at 9 celsius

b)what volume would this oxygen occupy at 26 celsius and 0.95 atm

plz show work and how

1 Answer

  • Moles O2 = 290 g / 32 g/mol =9.06

    T = 273 + 9 = 282 K

    p = nRT/ V = 9.06 x 0.0821 x 282 / 2.3 = 91.2 atm

    T = 26 + 273 =299 K

    V = nRT /p = 9.06 x 0.0821 x 299 / 0.95 = 234 L

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