a steel block has a volume of 0.08 m3 and a density of 7,840 kg/m3. What is the force of gravity acting on the

block (the weight) in water?

A: 5,362.56 N

B: 6,150.64 N

C: 6,700.56 N

D: 7,600.18 N

4 Answers

  • letter b is the answer.. because the weight of the object is approx. 627.20kg multiplied by 9.8(acceleration due to gravity) so the product is the force..

  • 16. A steel block has a volume of 0.08 m³ and a density of 7,840 kg/m³. What is the force of gravity acting on the block (the weight) in water?

    A. 6,700.56 N

    B. 7,600.18 N

    C. 5,362.56 N

    D. 6,150.64 N

    Student Answer: D

    Answer: Incorrect

    The correct answer is: 5,362.56 N

  • Im particular you comprehend that F = ma thus, a = g = 9.8 m/s^2 all we make sure is the mass of the article in kilograms we've the quantity and the density, thats all we make sure mass = quantity * density mass = .08 m3 * 7840 kg/m3 = 627.2 kg F = 627.2 kg * 9.8 m/s^2 F = 6146.fifty six newtons appears like plenty

  • no matter where the steel is (horizontally), the force of gravity acting on the steel is constant.

    Acceleration due to gravity is 9.8m/s2. (depends on how far you are from the core of the earth)

    Mass of 0.08m3 steel = 7840 X 0.08 = 627.2kg

    Force, F=ma. Therefore,

    F= 627.2 X 9.8 = 6146.56, close to answer B

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