a student slides a 0.75 kg textbook across a table, and it comes to rest after traveling 1.2m. Given that the coefficient of kinetic friction between the book and the table is 0.34, use the workkinetic energy theorem to find the book's initial speed.
1 Answer

Here frictional force= m*g*coefficient of kinetic friction
= 0.75 * 9.8 * 0.34
=2.499 Newton
Now, Acceleration of the book = force/mass
=2.499/0.75
=3.332
and distance=1.2m
So using the formula V*V = u*u + 2as
V= 0 m/s, a=3.332 and s=1.2
so 0 = u*u +2* (3.332)*1.2
therefore, u=2.83 m/s
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