Abuffer contains significant amounts of ammonia and ammonium chloride. part a write an equation showing how this buffer neutralizes added acid (hi).
When HI is added, the buffer reacts in the following way:
1) Neutralizing of the Acid:
HI + NH₄OH → NH₄I + H₂O
2) Dissociation of the salt of a weak acid:
NH₄I → NH₄⁺(aq) + I⁻ (aq)
3) Dissociation of a weak acid to form H₃O⁺ (very little):
NH₄⁺ + H₂O ⇄ NH₃ + H₃O⁺
This series of reactions show how the adding of a strong Acid can be neutralized by the buffer, releasing instead very little amounts of Hydronium ions.
Have a nice day!
Explanations:- KOH is a strong base that gives hydroxides ion in the aqueous solution. When it's added to a buffer solution, this hydroxide ion is neutralized by the weak acid, HA present in the buffer and try to maintain it's pH.
Ba(OH)2 + 2HCl ===> BaCl2 + 2H2O ; producing a salt BaCl2 and water.
or we can add H2SO4 to produce:
Ba(OH)2 + H2SO4 ===> BaSO4 + 2H2O; producing a salt, BaSO4, and water.
The strong base is added to the buffer solution, then the salt reacts with base to form weak base and water, which does not alter the pH
NH₄Cl + CsOH → NH₃ + CsCl + H₂O
NH₄⁺ + OH⁻ → NH₃ + H₂O
When we add a strong acid to the buffer solution, the base NH₃ reacts with acid and forms salt, which does not alter the pH
NH₃ + H⁺ → NH₄⁺
CH₃COO⁻ + HNO₃ → CH₃COOH + NO₃⁻
Buffer converts strong acid to weak acid