An electron and a proton are fixed at a separation distance of 881 nm. Find the magnitude and direction of the?

An electron and a proton are fixed at a separation distance of 881 nm. Find the magnitude of the electric field at their midpoint.

Magnitude: Please answer in N/C. Thank you! 🙂

1 Answer

  • At the midpoint, the electric field direction due to the electron is toward it.

    The electric field direction due to the proton is also toward the electron.

    E = k(2e)/(d/2)²

    E = 8ke / d²

    E = 8(8.99e9 N-m²/C²)(1.609e-19 C) / (8.81e-7 m)²

    E = 1.49e4 N/C

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