Beverly and Carl are in a race. Their graphs show the data. A graph with horizontal axis time (seconds) and vertical axis velocity

Beverly and Carl are in a race. Their graphs show the data. A graph with horizontal axis time (seconds) and vertical axis velocity (meters per second). An orange line labeled Beverly starts at 0 seconds 0 meters and goes straight to 10 seconds 15 meters and then to 50 seconds 35 meters. A blue line labeled starts at 0 seconds 0 meters and goes straight to 10 seconds 10 meters and then to 50 seconds 30 meters. Which best describes the race? Even though for a majority of the race they accelerated at the same rate, Carl won because his initial acceleration was greater than Beverly’s. Even though for a majority of the race they accelerated at the same rate, Beverly won because her initial acceleration was greater than Carl’s. Beverly accelerated at a greater rate for the entire race. Carl accelerated at a greater rate for the entire race.

Answers

C. The downward component of the projectile's velocity continually increases

Explanation:

The motion of a projectile consists of two independent motions:  

- A uniform motion (with constant velocity) along the horizontal direction  

- A uniformly accelerated motion, with constant acceleration (equal to the acceleration of gravity) in the downward direction  

Here we want to study the downward component of the projectile's velocity. Since the vertical motion is a uniformly accelerated motion, the vertical velocity is given by:

v=u+at

where

u = 0 is the initial vertical velocity (zero since the projectile is fired horizontally)

a=g=9.8 m/s^2 downward is the acceleration of gravity

t is the time

So the equation becomes

v=gt

This means that

C. The downward component of the projectile's velocity continually increases

Because every second, it increases by 9.8 m/s in the downward direction.

Learn more about projectile motion:

#LearnwithBrainly

Explanation:

velocity of projection = vo

angle of projection = θ

When the ball is at maximum height, its vertical component of velocity is zero, So it has only the horizontal component of velocity at highest point.

velocity at highest point = vo Cos θ

The acceleration acting on the ball is only the acceleration due to gravity which always acts vertically downward.

So, teh acceleration of the ball at the highest point is g.

Option E is correct.

There must be a horizontal wind opposite the direction of the stone's motion, because ignoring air resistance when calculating the horizontal range would yield a value greater than 32 m.

Explanation:

Normally, ignoring air resistance, for projectile motion, the range (horizontal distance teavelled) of the motion is given as

R = (u² sin 2θ)/g

where

u = initial velocity of the projectile = 20 m/s

θ = angle above the horizontal at which the projectile was launched = 30°

g = acceleration due to gravity = 9.8 m/s²

R = (30² sin 60°) ÷ 9.8

R = 78.53 m

So, Normally, the stone should travel a horizontal distance of 78.53 m. So, travelling a horizontal distance of 32 m (less than half of what the range should be without air resistance) means that, the motion of the stone was impeded, hence, option E is correct.

There must be a horizontal wind opposite the direction of the stone's motion, because ignoring air resistance when calculating the horizontal range would yield a value greater than 32 m.

Hope this Helps!!!

Yes 25.7677 is the amount of motion

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