Calculate [h+] for a solution in which [oh−] is 100 times greater than [h+].

A solution in which [OH?] is 100 times greater than [H+].
Express your answer using two significant figures.

Answer

In a neutral solution;
[H+] = [OH-] = 1×10^-7 M

Since [OH-] greater than [H+], the solution is basic.

In all solutions, whether neutral, or acidic or basic,
Kwater should be satisfied.
Kw = [H+][OH-] = 1×10^-14

Since [OH-] = 100[H+]

Kw = [H+] x 100 [H+] = 1×10^-14
[H+]^2 = 1×10^-14 / 100 = 1×10^-16

[H+] = 1×10^-8 M

Check:
[OH-] = Kw / [H+] = 1×10^-14 / 1×10^-8 = 1×10^-6 which is 100 times greater than 1×10^-8

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