Calculate the fraction of atom sites that are vacant for copper (cu) at its melting temperature of 1084°c (1357 k). assume an energy

Calculate the fraction of atom sites that are vacant for copper (cu) at its melting temperature of 1084°c (1357 k). assume an energy for vacancy formation of 0.90 ev/atom. (b) repeat this calculation at room temperature (298 k). (c) what is ratio of nv /n(1357 k) and nv /n(298 k)?

Answers

We know , vacancy concentration is given by :

dfrac{N_v}{N_t}=e^-({dfrac{Qv}{kT}})

Here , k=8.62times 10^{-5} eV/atom  K . ( Boltzmann's constant )

T = Absolute temperature in Kelvin .

Now ,

dfrac{(dfrac{N_v}{N_t})_{1232 K}}{(dfrac{N_v}{N_t})_{298 K}}\\\=dfrac{2.087times 10^{-4}}{6.08 times 10^{-16}}\\=3.432times 10^{11}

Hence , this is the required solution .

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