Activity C (continued from previous page) 3. Calculate: Use the Gizmo to mix 200 g of granite at 100 °C with 1,000 g of water at 20°C. A. What is the final temperature?_22.93°C B. Calculate the temperature change of each substance by subtracting the initial temperature from the final temperature. AT water: 2.9390 AT granto: -77.07 122 59.12 J 9-(2000)4181)(2 93) C. How much heat energy (9) did the water gain? – D. Now solve for the specific heat (c) of granite: __6.795.J/g°C E. Repeat steps A through D to find the specific heat (c) of lead: _0013 Jlgºc 4 129 sau / 200 23.675 Do#y ONLY Challenge: Use the specific heat capacity that you calculated for granite to determine how many grams of granite at the initial temperature of 80 °C must mix with 3,000 g of water at the initial temperature of 20 °C to result in a final system temperature of 20.45 °C. (Hint: Start by calculating how much heat energy is needed to change the water’s temperature by 0.45 °C). Show your work. Use the Gizmo to check your answer. Mass of granite = Al’ve included the granite info needed for this question dwide by

## Answer

specific heat capacity of water = 4.18 J/g
°*C ( have to learn for this )*
Heat energy needed to change the water temperature
Q = m . c .
T
Q = (3000g) . (4.18 J/g °*C) . ( 0.45*
°*C)*
*Q = 5643 J*
* For mass of
granite*
T
= 80°

*C – 20.45*°

*C 59.55*°

*C*

*Q = m . c . T*

*5643 = m . (0.79 J/g*°

*C) . (59.55*°

*C)*

*5643 = m . 47.04*

*m = 112 g*

*therefore , mass of granite is 112 g*

*Here is your answer. Thank you.*

*Please Thumbs up.*

We were unable to transcribe this image

We were unable to transcribe this image

We were unable to transcribe this image

We were unable to transcribe this image

We were unable to transcribe this image