Chemistry Help: Which of the following species has the greatest number of electrons?

Which of the following species has the greatest

number of electrons?

1. Al+

2. Si2+

3. Na+

4. Mg−

5. Mg

6. Al2+

7. Na−

8. P3+

Can you please explain how you got the answer? I never really understood this in class.

Thank you! <3

2 Answers

  • The general formula for this problem is

    Atomic number – the charge = the number of electrons.

    Al Atomic number = 13

    Al – 1 = the number of electrons.

    13 – 1 = 12 So this species has 12 electrons left.

    Si = 14

    Si – 2 = number of electrons.

    14 – 2 = 12

    Magnesium = 12

    12 – (-1) = 13

    Note: Mg would be hard pressed to take on an electron. Also note how the extra electron contributes a second minus sign. That’s because an electron is minus and the formula asks us to use a minus.

    Mg [no charge]

    Mg – 0 = number of electrons.

    12 – 0 = 12

    I’ll let you do the rest of them. Just use the formula.

  • The element’s periodic table number represents the number of Electrons the atom has originally. If it is positively charged then it has that many less electrons and if its negatively charged it has that many more electrons so

    Al normally has 13

    Al+ has 12

    Si normally has 14

    Si2+ has 12

    Na normally has 11

    Na+ has 10

    Mg has 12

    Mg- has 13

    Al2+ has 11

    Na- has 12

    P normally has 15

    P3+ has 12

    So Mg- has the greatest number of electrons

    Source(s): 3 Years of Chemistry

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