A concentration cell consists of two Sn/Sn2+ half cells. The cell has a potential of 0.11 V at 25 degrees Celsius.
What is the ratio of the Sn^2+ concentrations in the two half-cells?
Thank you so much for all your help!!
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Sn + Sn2+ (x M) —–> Sn + Sn2+ (y M)
Ecell = Eocell – (0.0591/2) log ([Sn2+ (y M)] / [Sn2+ (x M)])
0.11 = 0 – (0.0296) log x
log x = 0.11 / (-0.0296) = -3.7
x = 10^-3.7 = 0.00019 = ([Sn2+ (y M)] / [Sn2+ (x M)]
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