Consider an electron in the state n=4, l=3, m=2, s=1/2.
In what shell is this electron located?
-I put 4 but it said it was wrong.
What is the orbital angular momentum L of this electron in h(bar)s?
What is the z component of the orbital angular momentum of this electron, Lz?
What is the z component of the spin angular momentum of this electron, Sz?
If L is sqrt(12) h then it should be 3.46 * 6.6*10^-34. I’m getting 2.29*10^-33 and it’s saying I’m wrong.
If L is sqrt(12) h then it should be 3.46 * 6.6*10^-34. I’m getting 2.29*10^-33 and it’s saying I’m wrong.
Nevermind. The answer is the square root of 12.
Nevermind. The answer is the square root of 12.
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Shells sometimes have letters associated with them, starting with K:
n=1 -> K
n=2 -> L
n=3 -> M
n=4 -> N
So try “N-shell” .
L = sqrt(l (l+1) ) hbar = sqrt(12) h
Lz = m hbar = 2hbar
Sz = s hbar = 1/2 hbar
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