Consider the neutralization reaction below: 2HNO3 + Ba(OH)2 -> 2H2O + Ba(NO3)2.?

A 0.115-L sample of an unknown HNO3 solution required 48.7 mL of 0.100 M Ba(OH)2 for complete neutralization. What was the concentration of the HNO3 solution?

Please answer in Moles!

1 Answer

  • ( 48.7 mL) x (0.100 M Ba(OH)2) x (2 mol HNO3 / 1 mol Ba(OH)2) / (115 mL HNO3) = 0.0847 M HNO3

    [“Moles” are not a unit of concentration.]

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