Consider this reaction: 4NH3(g) + 3O2(g) –> 2N2(g) + 6H20(g)?

If the rate of formation of N2 is 0.10 M s-1, what is the corresponding rate of disappearance of O2?

1: 0.10 M s-1

2: 0.15 M s-1

3: 0.30 M s-1

4: 1.5 M s-1

1 Answer

  • In order to form 2 moles of N2, 3 moles of O2 would need to react, so

    0.10 M N2 s^-1 x 3 moles O2/2 moles N2 = 0.15 M O2 s^-1

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