Determine the electron geometry (eg) and molecular geometry (mg) of the underlined atom CH3OCH3.
eg=trigonal bipyramidal, mg=tetrahedral
eg=octahedral, mg=square planar
The electron domine around the carbon 1 is 4 (four bonding). Therefore, electron geometry and molecular geometry is tetrahedral Around Cl: eg tetrahedral mg - tetrahedral The electron domine around the oxygen atom is 4 (two bonding and two non bonding). Therefore, the electron geometry around oxygen is tetrahedral and molecular geometry is Bent. Around O: eg tetrahedral mg Bent The electron domine around the carbon 1 is 4 (four bonding ). Therefore, electron geometry and molecular geometry is tetrahedral. Around C2: eg tetrahedral mg tetrahedral
Both carbons are sp hybridized. Hence the correct answer is tetrahedral, tetrahedral.