Determine the maximum height above ground, hmax in meters, attained by the golf ball.?

A famous golfer strikes a golf ball on the ground, giving it an initial velocity v = v0xi + v0yj. Assume the ball moves without air resistance and its motion is described using a Cartesian coordinate system with its origin located at the ballʼs initial position.

v0x = 6 m/s

v0y = 3.4 m/s

2 Answers

  • Em = Ep + Ec = m.g.z + m.V²/2 = cste

    g.z○ + V○x²/2 + V○z²/2 = g.z○ + g.h + V○x²/2 + 0

    h = V○z²/(2.g) = 3,4^2/2/9,81 = 0,589194699 = 0,59 m

    ◙◙◙◙◙

    Az = d²z/dt² = – g

    Vz = dz/dt = V○z – g.t

    Dz = z-z○ = V○z.t – g.t²/2

    Vz(T) = 0

    T = V○z/g

    Dz(T) = h = V○z²/(2.g) = 0,59 m

     

  • use vf = vi + at and remedy for vi whilst t = 4.5 and a = -32 and vf = 0 using fact its at its maximum then use that vi (that’s a hundred and forty four ft/s) interior the equation d = vit + a million/2at^2 t = 5.7 (4.5+a million.2) very final answer could be 3 hundred.ninety six ft

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