Determine the oxidation number of the highlighted atom in the following structure:

Determine the oxidation number of the highlighted

Answer

The sum of the oxidation numbers of all of the atoms in a neutral compound is 0.

(CH_3)3-C-OH

Oxidation state of O= -2, (-1 in peroxide)
Oxidation state of H= +1, (-1 in metalic hydride)

C is more electronegative than H, so C posses negative and H posses positive oxidation state.

-CH_3 on a whole has oxidation state =0

The 1,2, and 3 C has 3 hydrogens 3H= +3 therefore these C has oxidation state C=-3.

O is electronegative than C, thus O is negative and C is positive.

-C-OH on a whole has oxidation state = 0

The C has 1H = +1and 1O = -2, therefore the oxidation state of

C-2+1=0

C=+1

To determine the oxidation states in organic compounds we need to analyze every bond of carbon as it tend to be different for each C of molecule according to the nearby more electron negative O or H atoms.

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