Determine the product(s) formed in the following reactions.

Questions & Products with mechanism (A CH3 mull DCHECO Cty 2 ho (Boduct) . ,H₂C OH 해 ave carried in 2nd o trochanism: – Negative charge of Chzc attacks on the electron charge opens will abstract it from water Step of form OH. After that on Auth Carbon of keepéug ‘ the stereo similar as teactant potation of bonds on 3rd Carbon, the stereo of product is decided. DCHECO CH OH 애 CECH Him KIH Hiro OH 2H VINH the CH₃ CH3 H₂ C CH₃ H₂C CH3 CECH OH ra 앰 COCH .60 Rotate Н H H -CH₃ HG CH₂ , HO- -CH3 HE IN H₂ CH3 CH₃ OH (Boduct) since, the quien structure @ is a symmetric epoxide, That’s why, attack on any electrophilie carbou centre will give sinflar product . B NICH3 CHEC H 2) H2O • Mechanism: — Negative charge of CH=C(nucleophild attacks on both electrophilie. “caubous al yields 2 products with different stereochemistry & the mechanism is as It Hairy OH OH CH₃ follows an

CECH AH OH CECH Hin ffichz DHCECO Hilm Annar , funners HIND ‘H thC H HC HC He=ce CECH OH 애 HEC OQ CH3 H Janinch H SCH₃ Hoy H₂C Go Rotation Lokalt H.C CECH HCEC OH Hon -H the 11 CH3 Himonio the fuchs H OH 애 CECH -H ( OH (н “CH3 Products CH3 3 CECH CH3 CECH CH3 H ☺ OH H -CH2 , Н H ОН H H CHA OH Since, no plave of symmetry is seen in starching compound So, the ‘d given” preduets are possible.