Help me with this problem pleaseeee.

The answer choices given are:

1) (5 sqrt2 , 315°), (-5 sqrt2 , 135°)

2) (5 sqrt2 , 45°), (-5 sqrt2 , 225°)

3) (5 sqrt2 , 135°), (-5 sqrt2 , 315°)

4) (5 sqrt2 , 225°), (-5 sqrt2, 45°)

### 2 Answers

Since the point lies in the third quadrant

cos(θ) = x/r where r^2 =x^2+y^2 =5^2(-5)^2 =25+25 = 50 , r = sqrt(50) =5sqrt(2)

cos(θ) = x/r =5/5sqrt(2) =1/sqrt(2) = cos(135)

Hence answer is = (5 sqrt2 , 315°), (-5 sqrt2 , 315°)……………….Ans

option 1) (5 sqrt2 , 315°), (-5 sqrt2 , 135°) is correct :)>