Difficult math equation that equals 3? (7th grade)?

4 Answers

  • This is the hardest 7th can get in Sweden---v

    6x + (3x - 5) = 22

    Answer: X = 3

  • log(300 / x) + √(x + 6) - (2)^(4 - x) + [(x + 2) / (x + 1)](4) = 8

    Source(s): As far as I know, without using Newtonian approximation, there is no way to solve this problem algebraically through separation of variables. Have fun!

    However, x = 3, as you can check it yourself.

  • x^3 + 3x^2 - 5x = 3

  • idiot who doesn't belong in 7th grade?

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