Find an equation of the tangent line to the curve at the given point. y = Squareroot x, (81, 9) y =

## Answer

y = Jr.(819) Differentiatıng with respect x, we get dx 2V812(9) 18 The equation of tangent with slope 13 and the point (819) is y-9–(x-81) 181 1818 18 2 182 -9+18 18 2