# Find the cube roots of 8(cos 216° + i sin 216°).

Find the cube roots of 8(cos 216° + i sin 216°).

where . So the third roots are

Start at k = 0, 1, 2, because there are THREE cube roots of a complex number:

k = 0: 2(cos 72° + i sin 72°)
k = 1: 2(cos 192° + i sin 192°)
k = 2: 2(cos 312° + i sin 312°)

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