I’ve already figured out how to find the current through resistor a, but I can’t figure it out for resistor b, and I really need that part to finish the rest of the problem. please explain!! thank you!

ALSO. would the current for resistor C be the same as a (0.60 A). and would resistor D be the same as resistor B?

I forgot to add that E = 6.0 V

### 1 Answer

c and d are in series, so their equivalent resistance is 10 Ohms. That 10 Ohms is in parallel with b which is 10 Ohms. So the b,c,d equivalent is 5 Ohms. And that 5 Ohms is in series with A which is 5 Ohms. So all 4 resistors have an equivalent resistance of 10 Ohms. The figure does not say what E is but the current that goes out into the network is E/10 Ohms.

At the node that is common with resistors a, b, and c; the current will divide in 2 equal parts. So the current in b is (1/2)*E/10 Ohms. The current in the c&d branch is also (1/2)*E/10 Ohms.

Ah. E=6 So E/10 Ohms = 0.6 A. (1/2)*E/10 Ohms = 0.3 A