find the differential of each function please.
y = s / (2+5s)
and...
y = u ( cos(u) )
THANKS!
3 Answers

Hello,
y = s / (2+5s)
dy = (ds(2+5s)  5s ds_/(2 + 5s)^2 = (2ds +5sds 5sds)/(2 + 45s)^2
Then dy = 2ds/(2+5s)^2 or (2/(2+5s)^2)ds
y = u ( cos(u) )
dy = du(cos(u)) + u(sin(u))du = (cos(u) u sin(u)) du
Hope This Helps!

for the first 1:
y = 2/(2+5s)^2
and second 1:
y= u(sin(u))x(cos (u))
i hope thts right! x

y = s / (2+5s)
Apply the Quotient Rule:
dy /ds = [(2+5s)(1)s(5)] / (2+5s)^2
dy/ds = 2/(2+5s)^2
dy = 2ds / (2+5s)^2

y= u cos(u)
dy/du = cos(u)usin(u)
dy = cos(u)du  usin(u)du