Find the dimensions of a rectangle with perimeter 108 m whose area is as large as possible?

3 Answers

  • A square is the rectangle required for maximum area.

    If the perimeter is 108, the sides will be 108/4 = 27m

  • The dimensions of a rectangle with perimeter 108 m

    whose area is as large as possible?

    For the rectangle to have the maximum area, the dimensions should be equal.

    Let the dimensions be x

    thus the perimeter will be:

    2(x + x) = 108

    2(2x) = 108

    4x = 108

    x = 27

    thus for the rectangle to have a maximum area the dimensions should be 27m by 27 m

    Read more on Brainly.com – https://brainly.com/question/9174422#readmore

  • That would be a square — 4 equal sides.

    108/4 = 27 m

    Answer:

    27 m by 27 m

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