### 3 Answers

A square is the rectangle required for maximum area.

If the perimeter is 108, the sides will be 108/4 = 27m

The dimensions of a rectangle with perimeter 108 m

whose area is as large as possible?

For the rectangle to have the maximum area, the dimensions should be equal.

Let the dimensions be x

thus the perimeter will be:

2(x + x) = 108

2(2x) = 108

4x = 108

x = 27

thus for the rectangle to have a maximum area the dimensions should be 27m by 27 m

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That would be a square — 4 equal sides.

108/4 = 27 m

Answer:

27 m by 27 m