Can someone help with this problem, I’ve tried all sorts of equations to figure this out, but cant get the right answer. Thanks!
1 Answer

start with balanced equation:
3 HCl + Al(OH)3 —> AlCl3 + 3 H2O
MW Al(OH)3 = 78.00344 g/mol so 1.55g / MW = 0.0200 moles aluminum hydroxide
you need 3 x 0.0200 moles HCl according to the formula.
0.0600 moles HCl / 0.130 moles/L = 0.46 L = 460 mL