For the reaction 2 NH3 + CH3OH ! products , how much CH3OH is needed to react with 93.5 g of NH3?

Can someone please explain how to solve the problem.

The multiple choice answers are as followed:

  1. 46.8 mol

  2. 88.1 mol

  3. 2.75 mol

  4. 3.32 mol

  5. 11.3 mol

  6. 5.50 mol

  7. 1.31 mol

1 Answer

  • MW: NH3 = 17, CH3OH = 32

  • moles of NH3 = 93.5/17 = 5.5

    according to the equation, 1/2 mol methanol reacts with each mol of ammonia, so it would take 5.5/2 or 2.75 mol.

    answer is no 3.

Leave a Comment