Assuming equal concentrations, rank these aqueous solutions by their freezing point: SnBr4, Na2CO3, LiNO3, Li3PO4.
I am confused, because I keep finding the ion particles, like Na2CO3 has 3, but I don’t know where SNBr4 comes into place. Can someone please help? Please explain your answers so I can follow you. Thank you!
For SnBr4, when dissolved, there is 1 Sn^4+ and 4 Br^-, total = 5 ions.
Na2CO3 has 3 ions, LiNO3 has 2 ions, and Li3PO4 has 4 ions.