Freezing point… help please?

Assuming equal concentrations, rank these aqueous solutions by their freezing point: SnBr4, Na2CO3, LiNO3, Li3PO4.

I am confused, because I keep finding the ion particles, like Na2CO3 has 3, but I don’t know where SNBr4 comes into place. Can someone please help? Please explain your answers so I can follow you. Thank you!

1 Answer

  • For SnBr4, when dissolved, there is 1 Sn^4+ and 4 Br^-, total = 5 ions.

    Na2CO3 has 3 ions, LiNO3 has 2 ions, and Li3PO4 has 4 ions.

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