# How do I do this chemistry problem?

How many moles of (CH3)3NH+ are in 6.0 g of (CH3)3NH+?

• Molar mass (CH3)3NH+ = 12.011*3 + 1.008*10 + 14.007 = 60.12

If you have 6g you will have 6/60 = 0.1 moles

• Taking atomic mass of C 12, N 14 and H1

Molecular Wt. of (CH3)3NH+ = 60

So no. of moles (CH3)3NH+ in 6.0g = 6/60 = 0.1

So 6 g of (CH3)3NH+ contains 0.1 moles of it.

This is simplified answer,

Now consult your book take exact mass of the atoms , like H= 1.008 g, N = 14.0067g, C= 12.011g and recalculate it.

Answer will differ very slightly.

• first you calculate the molar mass of (CH3)3NH+, which i think is around 60g/mol? im not that sure but you get this by adding the molar masses of each individual atom.

like for example the molar mass of carbon is est 12 then multiply this by 3 since there are a total of 3 atoms in the ion. then add them all.

yea anyway after getting the molar mass, you simply divide the mass [which is 6.0g] by the molar mass. then you get the number of moles.

• first you need to know how many grams are in 1 mole of the molecule. To do this you add up the atomic mass of each atom in the molecule. So we have:

3xC + 10xH + 1xN

=3×12.01 + 10×1.008 + 14.01

=60.12

So in 1 mole there is 60.12 g, so in 6 grams, there is 6.0/60.12 which is approximately 0.10 moles

• when i have these kind of problems i follow a rule

n=m/M

or (n) equals (little m) over (big M)

n – is the number of moles

little m – is the mass in grams

big M – is the molar mass of the product.

n= ?

m = 6.0g

M= (12+ (3*1.008))*3 + 14 + 1.008 = 60.08

so now n=m/M

n=6/60.08

so therefore n= 0.1moles

• 0.10 moles.