how do you calculate the molar mass of MnSO4*H2O?

5 Answers

  • Calculations:

    Formula: MnSO4.H2O

    Molar Mass: 169.0088 g/mol 1g=5.91685166689545E-03 mol

    Percent composition (by mass):

    Element count Atom Mass %(by mass)

    Mn 1 54.938 32.51%

    S 1 32.06 18.97%

    O 5 15.999 47.33%

    H 2 1.0079 1.19%

    You can calculate it at this websites.

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    RE:

    how do you calculate the molar mass of MnSO4*H2O?

  • Mnso4 H2o

  • Well, if you divide the 9.38 kJ by the 2.60 kJ/mol you will find out how many moles of the substance were involved. 9.38 / 2.60 = 3.61 moles Remeber the little formula n = m / M? Well you now have a mass (m) and the moles (n) , solve for M M = m / n 48.7 g / 3.61 moles = 13.5 g/mol

  • https://shorturl.im/ZevDB

    2.60 kJ/mol 9.38 kJ/48.7g = 0.192 kj/g 2.60 kJ/mol/ (0.192 kj/g) =13.54 g/mol

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