how do you convert 3x-5y+2=0 to polar form?

1 Answer

  • x = r cos θ

    y = r sin θ

    Hence 3x – 5y + 2 =0 becomes

    3rcos θ – 5rsin θ + 2 = 0

    r(3cos θ – 5sin θ) + 2 = 0

    r = -2 / (3cos θ – 5sin θ)

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