# How many atoms are in 1.14 moles of SO3?

so far nobody has got the correct answer…

• use Avogadro constant (symbols: L, NA), also called the Avogadro number N(A)= 6.02 x 10^23 mol^-1 1 mole of SO3 will contain 6.02 x 10^23 mol^-1 of SO3 molecules. thus, 1.14moles will contain; = 1.14mol x [3mol O/1mol SO3] x [6.02 x 10^23 atoms O/1mol O] = 2.05884 x 10^24 oxygen atoms = 1.14mol x [1mol S/1mol SO3] x [6.02 x 10^23 atoms O/1mol O] = 6.8628 x 10^23 sulfur atoms hope this helps:-)

• There are a total of 4 atoms in one molecule of SO3. So if we have 1.14 moles of SO3 then we have 1.14 x 4 = 4.56 moles of atoms then we’ll multiply by avagadro’s number: 4.56 x (6.02 x 10^23) = 27.5 x 10^23 atoms = 2.75 x 10^24 atoms

• there are Avogadro’s number of molecules per mole. Avogadro’s number is 6.02×10^23 molecules/mole or atoms/gram-atom

Therefore 1.14×6.02= 6.86 x10^23 molecules of SO3 with 4 atoms per molecule = 4×6.86×10^23 atoms=27.44 x 10^23 atoms or 2.744×10^24 atoms

• 1.14 moles x 6.02 x 10>23

• 1

• Perhaps you are not asking the right question.