How many Li atoms are contained in 97.9g of Li?

Just verifying my answers for some hw


5 Answers

  • 1. The first thing you need to figure out is how many MOLS of Li there are in 97.9g of Li.

    a. The conversion factor for this is ATOMIC MASS: there are 6.941g of Li for every mol of Li

    b. so, to find the number of mols, divide: 97.9g Li/(6.941g Li/mol Li). This gives you 14.1 mol Li

    2. Now, you can figure out how many ATOMS there are in 14.1 mol Li.

    a. There are 6.022 x 10^23 atoms in a mol

    b. to find the number of atoms in 14.1 mol Li, multiply: 6.022 x 10^23 atoms/mol * 14.1 mol

    The answer I get is 8.49 * 10^24 Li atoms

  • 97.9/6.941 = 14.10

    14.10 x 6.022×10^23 = 8.49×10^24

  • hmm

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