How many molecules are present in 4.25 mol of CCl4?

A)9.26 × 1025

B)2.56 × 1024

C)653.69

D)153.81

E)36.91

I’m confused, because I was getting 2.7099 × 10^24 and that isn’t an option, so am I leaving out a step?

3 Answers

  • mol= # of molecules or atoms/ 6.022 x 10^23

    4.25= x/ 6.022 x 10^23

    x= 2.56 x 10^24 (after taking into account sig figs)

    B

  • B

    multiply 4.25 by 6.02 x 10^23

  • 4.25×6.022×10^23=2.56×106^25

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