How many moles of Cu are in 1.48 × 1025 Cu atoms?

How many moles of Cu are in 1.48 × 1025 Cu atoms?

Answers

1 mole 6.02 x 10²³ atoms
( moles Cu) 1.48 x 10²⁵ atoms

moles Cu =  ( 1.48 x 10²⁵ ) x 1 / 6.02 x 10²³

moles Cu = 1.48 x 10²⁵ / 6.02 x 10²³

= 24.58 moles of Cu

hope this helps!

1.48 * 1021 number of molecules of pentane = 0.0002458 mol

Given data:

Number of molecules of pentane = 1.48 * 1021

Number of moles = ?

Solution:

1 mole = 6.02 × 1023 molecules.

If

1 molecule = 1/6.02 × 1023

So

1.48 × 1021 molecules = (1/6.02 × 1023) × 1.48 × 1021

                                    = 2.458 × 10-3 mol

                                    = 0.0002458 mol

So there are 0.000245 moles of pentane, if the number of molecules are 1.48 * 1021. Because 1 mole mole contain Avogadro's number of molecules.

Which is equal to 6.02 × 1023 molecules.

multiply the number of each atom with its molecular mass. (see the periodic table)

5*12 + 12*1 = 72 gram per mole.

Or more accurately: 5*12.01078 + 12*1.007947 = 72.149264 g/mole

24.6 mol Cu

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Atomic Structure

MolesAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Using Dimensional AnalysisExplanation:

Step 1: Define

[Given] 1.48 × 10²⁵ atoms Cu

[Solve] moles Cu

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

[DA] Set up:                                                                                                     displaystyle 1.48 cdot 10^{25}  atoms  Cu(frac{1  mol  Cu}{6.022 cdot 10^{23}  atoms  Cu})[DA] Divide [Cancel out units]:                                                                       displaystyle 24.5766  mol  Cu

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

24.5766 mol Cu ≈ 24.6 mol Cu

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