How much heat is required to warm 1.70 kg of sand from 30.0 ∘C to 100.0 ∘C? The specific heat capacity of sand is Cs=0.84J/g⋅∘C.?

1 Answer

  • Q = m*c*delta-T

    = (1700 grams)(0.84 J/(gram degC))*(70 degC)

    = (119)(0.84) kJ

    = about 100 kJ but use a calculator.

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