math homework, appreciate help!
15 Answers
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Not that 4*4=16 and 16*4=64. So, 4*4*4 = 16*4 = 64. Thus, the cube root of 64 is 4.
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The long form solving of a cube root begins with the knowledge of a few basic cube roots including “64”.
I’m not sure what your teacher is looking for but you could demonstrate a trial and error approach:
Attempt 1: 3*3*3=27
Attempt 2: 5*5*5=125
Attempt 3: 4*4*4=64 Success!
As far as I know, long form cube roots requires a memorized set of the basic cubes of 2,3,4,5,6,7,8 and 9. Getting the cube of 65 for example starts with a knowledge that 4 cubed is 64.
4.
3/———–
/ 65
-64
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1.000
The next decimal would be a value of x that would make the next equation less than 1000 for:
(4^2 *300 + 4*30 * X+X^2 ) * X
in this case X = 0
So the solution is tending towards 4.0_ _ _
Eventually, you will get 4.02 using this method. But as you can see, I needed to know off the start that 4 was the cube of 64. This can only be “PROVEN” via the forwards of:
4*4=16
16*4 = 64.
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Cube Root Of 64
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knowing that 64 = 8*8 and that the cube root of 8 = 2, i’d say the cube root of 64 = 2*2 = 4
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You factor it out to primes:
2*2*2*2*2*2 = 64
If you need the square root you would divide it into two sets: (2*2*2)(2*2*2)=8×8=64.
If you need the cube root you just divide it into three sets: (2*2)(2*2)(2*2)=4*4*4=64
The same thing could be done for sixth root.
So four is your answer, just through a few more examples up there.
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after a while you know this from problems you have done. so remember cube root of 64 = 4
4 * 4 * 4 = 64
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Just factorize it and get the answer
64 = 2^6
taking cube root => dividing power by 3
Therefore the answer is 2^2 = 4.
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Look at the prime factorization of 64:
64 = (2 x 2) x (2 x 2) x (2 x 2)
The terms can be associated into three identical groups, hence
CubeRoot(64) = (2 x 2) = 4
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4 x 4 x 4 = 64
Answer is 4
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factor out 64
64 = 8(8) = 2(4)(2)(4) = 4(4)(4)
so, cube root of 64 = cube root of [4(4)(4)] = 4
hope this helps