# How would you graph 4x+3y=6?

• First, subtract 4x from both sides–> 3y=-4x+6

Then, divide both sides by three–> y=(-4x+6)/3 –> y=-4/3x+2

2=b, the y-axis intercept, so make your starting point at (0,2), and then the slope is -4/3, i.e. the rise is -4 and the run is 3, so for every four spaces you move down from any point on the line (use the starting point to make the graph), move 3 spaces to the right. Hope that helps :]

• First, make y as subject of the formula

4x + 3y = 6

3y = 6 – 4x

y = (6 – 4x)/ 3

y = 2 – 4x/3

y = -4/3x + 2

Straight line is y = mx+c

m = -4/3

c = 2

So, it is a straight line graph. You can plot a graph with some points given.

• first, get it in the form y=mX+c by making y the subject

4x+3y=6

3y=6-4x

y=(6-4x)/3

Choose values for x and then using those values, find the corresponding ‘y’ values and plot the graph of a straight line.

• you would graph it as :

y= 2- 4/3x

or y= -4/3x + 2

b/c you have to solve for y

then graph

• Solve for y and then graph it like you would any other line.