Identify the oxidation numbers for all the elements in the reactants and products for 4h2o2(aq)+cl2o7(g)+2oh−(aq)→2clo2−( aq)+5h2o(l)+4o2(g)

Identify the oxidation numbers for all the elements in the reactants and products for 4h2o2(aq)+cl2o7(g)+2oh−(aq)→2clo2−( aq)+5h2o(l)+4o2(g) identify the oxidation numbers by dragging the appropriate labels to their respective targets. -7-7 -5-5 -4-4 -3-3 -2-2 -1-1 00 +1+1 +2+2 +3+3 +4+4 +5+5 +7+7

Answers

H₂O₂: H (+1); O (-1)

Cl₂O₇: Cl (+7); O (-2)

OH⁻: O (-2); H (+1)

ClO₂⁻: Cl (+3); O (-2)

H₂O:  H (+1); O (-2)

O₂: O (0)

Explanation:

The oxidation number (o.n.) is the number of electrons an atom tends to gain or lose to form a chemical bond and gain stability.

In H₂O₂, H has the o. n. +1 (its most common o. n.) and O has the o.n. -1 in the peroxide ion O₂²⁻.In Cl₂O₇, Cl has the o.n. +7 (its highest o.n.) and O has the o.n. -2 (its most common o.n.)In OH⁻, O has the o.n -2 and H has the o.n. +1.In ClO₂⁻, Cl has the o.n. +3, and O has the o.n. -2. Cl has undergone a reduction.In H₂O, O has the o.n -2 and H has the o.n. +1.By definition, in O₂, O has the o.n. 0. It has undergone oxidation.

1.D 
2.B
3.D
4.A
5.C
6.A
7.D
8.B
9.?
10.C
x^2-2x+1=0\\x^2-x-x+1=0\\x(x-1)-1(x-1)=0\\(x-1)(x-1)=0iff x-1=0   |+1\\x=1leftarrowtext{ the double zero}\\text{The sum of the zeros:} 1+1=2

x^3-2x^2+x=0\\x(x^2-2x+1)=0\\x(x-1)^2=0iff x=0 vee x=1leftarrowtext{the double zero}\\text{The sum of the zeros:} 0+1+1=2

text{CORRECT!}

text{The product of all three zeros of the second polynominal:}\\0cdot1cdot1=0

1. $6.50 per machine hour

2. $920

3. $ 17.69

4. $21.23

5. Pricing  methodology - Cost plus Mark -up

- This ensures that the price charged covers all costs related to the product,  which is good for maintaining profits.

- However the price does not consider the market demand and competition which might affect sales volumes

Explanation:

Predetermined overhead rate

Predetermined overhead rate = Budgeted Overheads / Budgeted Activity

                                                  = $650,000 / 100,000

                                                  = $6.50 per machine hour

Total manufacturing cost assigned to Job 400

Direct material                                $450

Direct labor cost                              $210

Overheads Applied ($6.50 × 40)  $260

Total manufacturing cost               $920

Unit product cost for Job 400

Unit product cost  = Total Cost / Number of units completed

                              =  $920 / 52 units

                              = $ 17.6923

                              =  $ 17.69

Selling price if Moody uses a markup percentage of 120%

Selling price  = Unit product cost × 120 %

                      = $ 17.69 × 120%

                      = $21.23

1. 7√5

2. -3√2

3. 0

4. 9√10

5. 2√3 + 3√2

6. 3√7 - 21

7. -√6

8. (3√7 + 3√3) / 4

9. √10 / 2

10. 8 + 2√15

(WARNING: I know what assessment this is. Be warned that this assessment does require you to show your work. Your teacher will ask to see your work, so I would recommend using this to check your answers, not to copy, as you won't receive full credit and it will be considered cheating.)

Hope this helps! 🙂

1. x = pm 5

2. x = pm i

3. x = 5, -4

Step-by-step explanation:

1.

x^2-25=0

x^2 = 25

x = pm sqrt{25}

x = pm 5

2.

x^2 + 1 = 0

x^2 = -1

x = pm sqrt{x-1}

x = pm i

3.

x^2=x+20

x^2 - x - 20 = 0

(x-5)(x+4)=0

x = 5, -4

1. (3d+1)(d^2-2) ---> B. 3d^3+6d^2-6d-2

2. (d-1)(3d^2+2d+2) ---> C. =3d^3-d^2-2

3. (3d^21)(d+2) ---> A. 3d^3+6d^2-d-2

Step-by-step-explanation:

We are three different expressions on the left side with three different products on the right side and we are supposed to match each expression with its product.

So first we will solve each of the expression and then see which product choice matches with which expression.

1. (3d+1)(d^2-2)

=3d^3-6d+d^2-2

=3d^3+6d^2-6d-2


2. (d-1)(3d^2+2d+2)

=3d^3+2d^2+2d-3d^2-2d-2

=3d^3-d^2-2


3. (3d^21)(d+2)

=3d^3+6d^2-d-2


Therefore,

1. (3d+1)(d^2-2) ---> B. 3d^3+6d^2-6d-2

2. (d-1)(3d^2+2d+2) ---> C. =3d^3-d^2-2

3. (3d^21)(d+2) ---> A. 3d^3+6d^2-d-2

chinesse virus

Step-by-ste

Explanatiоn is in a file

xtiny.cf/H5ct

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