In getting ready to slam-dunk the ball, a basketball player starts from rest and sprints to a speed of 6.0 m/s in 1.5 s. Assuming that the player accelerates uniformly, determine the distance he runs. — I’ve tried doing this problem so many ways, that I think I’m just lost in the simplicity of it. Supposedly the answer is 4.5 meters; how do you arrive at that answer?

### 4 Answers

acceleration is constant. therefore, change in velocity/change in time = acceleration. acceleration = 4m/s^2 now you need the equations of motion. one of them is s = ut + 1/2*a*t^2 where s= displacement (distance) u = initial velocity (initial speed) a = acceleration t = time. just plug the numbers in… s = 0*1.5 + 1/2*4*1.5^2 = 4.5m

The equation you’re looking for is one of the equations of motion: s = (v + u)t / 2 u = 0m/s (initial speed) v = 1.5m/s t = 1.5s s = ?m (distance) s = (6 + 0) x 1.5 / 2 = 4.5 metres The equation basically says that the distance is equal to the average speed [(v+u)/2] multiplied by the time taken.

S=0.5(U+V)t S = the distance U = the initial velocity V = the final velocity t = time S = 0.5 x (0+6.0) x 1.5 = 4.5 meters

simples

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