# In the figure, sin ∠MQP = .

In the figure, sin ∠MQP = .

cos R and sin N

Step-by-step explanation:

we know that

in the right triangle MNR

Because

--------> by complementary angles

so

sin ∠MQP=

therefore

D. Cos R and Sin N

we know that

in the right triangle MNR

Because

--------> by complementary angles

so

sin ∠MQP=

therefore

D. Cos R and Sin N

we know that

in the right triangle MNR

Because

--------> by complementary angles

so

sin ∠MQP=

therefore

D. Cos R and Sin N

Sin N  = NM/NR
Cos R  = NM/NR

D. Cos R and Sin N

The easiest way to get this problem correctly is by calculating the sines and cosines of all the angles in the choices then choosing the correct choice.

sin ∠MQP = sin(56) = 0.829
cos ∠N = cos(56) = 0.559
sin ∠R = sin(34) = 0.559
sin ∠N = sin(56) = 0.829
cos ∠N = cos(56) = 0.559
sin ∠M = sin(90) = 1
cos ∠R = cos(34) = 0.828

Based on these findings, it is obvious that sin ∠MQP is equal to cos ∠R and sin ∠N.
Thus, the correct choice is "d".

The easiest way to get this problem correctly is by calculating the sines and cosines of all the angles in the choices then choosing the correct choice.
sin ∠MQP = sin(56) = 0.829cos ∠N = cos(56) = 0.559sin ∠R = sin(34) = 0.559sin ∠N = sin(56) = 0.829cos ∠N = cos(56) = 0.559sin ∠M = sin(90) = 1cos ∠R = cos(34) = 0.828
Based on these findings, it is obvious that sin ∠MQP is equal to cos ∠R and sin ∠N.Thus, the correct choice is "cos R and sin N".

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