integrals of trigametrics?

wht is the anti derivative of sin^2(x)

2 Answers

  • 1) Cos(2x) = 1 - 2sin^2(x)

    2) Using this, sin^2(x) = [1 - cos(2x)]/(2)

    3) Now integrating this, we get, = (1/2)*[x - sin(2x)/2]

    Hence answer is = (1/4)*[2x - sin(2x)] + C

    Source(s): Self knowledge
  • > int(sin(x)^2, x) =

                              1                        1  
    
                           - --- sin(x)*cos(x) + ----x + C

    2 2

    Source(s): Maple 13.01

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