wht is the anti derivative of sin^2(x)
2 Answers

1) Cos(2x) = 1  2sin^2(x)
2) Using this, sin^2(x) = [1  cos(2x)]/(2)
3) Now integrating this, we get, = (1/2)*[x  sin(2x)/2]
Hence answer is = (1/4)*[2x  sin(2x)] + C
Source(s): Self knowledge 
> int(sin(x)^2, x) =
1 1   sin(x)*cos(x) + x + C
2 2
Source(s): Maple 13.01