11 Answers

Typically, American schools teach no more than two years of algebra. But algebra is a rich subject, one that you can study for many years, or even as a profession.
Once you’re in college, you can study the rules of algebra, and discover systems of numbers that have rules very different than your own! You can learn about number systems where you can divide by 0, ones where every number is a multiple of every other number, and all sorts of other strange notions.
If you enjoy algebra, studying math in college is an exciting option. Good luck in your studies.

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RE:
is there a such thing as algebra 3 or 4

No, there are more advanced algebra classes than algebra 2 that you can take in college but they aren’t called algebra 3 or 4.
EDIT: I stand corrected. It seems Scanderberry has a found a school that offers algebra 3. I’ve never heard of schools offering algebra 3 before though.

Yes, Virginia, there is an Algebra 3. In the school in which I teach the class focuses only on the Algebra part of PreCalculus. Our State (Arkansas) requires 4 math credits in order for a student to graduate; therefore the need for Algebra 3.

In high school? After Algebra 2 I took Analysis followed by Calculus. I’ve never heard of Algebra 3 or 4 but all schools are different check the course syllabus.

only in schools that count by semister instead of year
They sometimes call Algebra 1A and 1B as Algebra 1 and 2
That makes Algebra 2A and 2B into Algebra 3 and 4

my school offers a class called algebra 3 and the books say algebra 3 on it

A vertical asymptote occurs when the denominator = 0 Ex: f(x)=1/x the vertical asymptote would be x=0 For horizontal asymptotes it is a bit different. When the degree of the numerator is less than the degree of the denominator then the horizontal asymptote is y= 0 (ex. f(x)=1/x) When the degree of the numerator and denominator is the same the horizontal asymptote is equal to the division of the first coefficients (2x^25x+6)/(2x^22x+3) the asymptote would be y=2/2 =1 When the degree of the numerator is greater than the degree of the denominator then the asymptote is oblique (a line on the graph ex. y=x) Degree: is the highest exponent in poly/binomial

i dont think so, it goes algebra 1 geometry algebra 2 then calculus

Asalgebra