Liquid benzene (C6H6) reacts with gaseous oxygen to form carbon dioxide and liquid water?

1. When benzene (C6H6) reacts with oxygen, carbon dioxide and water are produced. The balanced equation for this reaction is:

2C6H6 (l) + 15O2 (g) Arrow.gif12CO2 (g) + 6H2O (g)

If 60 moles of oxygen react,

The reaction consumes moles of benzene (C6H6)
The reaction produces moles of carbon dioxide and

2.

48.7 mL of 0.664 M nitric acid is added to 40.9 mL of calcium hydroxide, and the resulting solution is found to be acidic.

29.9 mL of 0.579 M potassium hydroxide is required to reach neutrality.

What is the molarity of the original calcium hydroxide solution?

moles of water

Answer

General guidance

Concepts and reason

Chemical reaction can represented with the symbols of elements or molecules involved in the reaction, instead of providing the complete name of the substance, such a symbolic representation is called as chemical equation. Here reactant molecules are written on the left-hand side and product molecules are on the right-hand side, separated by the single headed arrow. Stoichiometry: Stoichiometry gives the quantitative relationship between the reactants and products of the chemical reaction. It helps to determine the relationship between the number of moles of the reactants and products that are involved in a reaction. For proper calculation, the reaction must be balanced. Molarity (M): It can be defined as the number of moles of solute that are dissolved per liter of solution.

Fundamentals

The stoichiometry of a reaction informs the optimum quantity of each of the reactants required for a complete reaction with no residual reactants. For a general reaction: aА+Ыв — > сС+dD According to the stoichiometry of the reaction, ‘a’ moles of Areact with ‘b’ moles of Вto produce ‘c’ moles of Cand‘d’ moles of. The molarity of a solution is calculated as shown below: Number of moles of solute
Molarity
Volume of solution in litres Hence, the number of moles of solute dissolved can be calculated by rearranging the equation as follows: Number of moles =MolarityxVolume of solution(L).

Step-by-step

Step 1 of 5

(1) The given reaction is given below: 2C H ()150, (g)
>12C0, (g)+6H,0(g)” title=”7707bd06715c”>

The number of moles of oxygen reacts<img decoding=. Therefore: The number of moles of C,H, reacts=60x2
15
8moles

From the given reaction, it is identified that two moles of benzene reacts with fifteen moles of oxygen to produce twelve moles of carbon dioxide and six moles of water. Therefore, the number of moles of benzene required to react with of oxygen is.

Step 2 of 5

The given reaction is given below: 2C H ()150, (g)
>12C0, (g)+6H,0(g)” title=”7707bd06715c”>

The number of moles of oxygen reacts<img decoding=. Therefore: The number of moles of CO, produced=00X12
15
48moles

According to the given reaction, it is identified that two moles of benzene react with fifteen moles of oxygen to produce twelve moles of carbon dioxide and six moles of water. Therefore, the number of moles of carbon dioxide produced whenof oxygen reacted are.

Step 3 of 5

The given reaction is given below: 2C H ()150, (g)
>12C0, (g)+6H,0(g)” title=”7707bd06715c”>

The number of moles of oxygen reacts<img decoding=. Therefore: The number of moles of H30 produced=o0Xo
15
24 moles

Part 1

When benzene(С,Н.)
6reacts with oxygen, carbon dioxide and water are produced. If 60molesof oxygen reacts: The reaction consumes
8 moles of benzene (C6H6)
48moles of carbon dioxide and
The reaction produces
24 moles ofwater


According to the given reaction, it is identified that two moles of benzene react with fifteen moles of oxygen to produce twelve moles of carbon dioxide and six moles of water. Therefore, the number of moles of water produced whenof oxygen reacted are.

Step 4 of 5

(2) The reaction between HNO and КОН takes place as given below: HNOKOH
>KNO, +H20″ title=”724012f2e2ab”>

Calculation of number of moles of nitric acid.

Volume of nitric acid,<img decoding=. Molarity of nitric acid solution, Molarity 0.664 M. The number of moles can be calculated by the equation as follows: No of moles=Molarityxvolume in ml
1000 No of moles of HNO.=Molarity of HNO, x volume of HNO, in mL
1000
0.664 Mx 48.7 mL
1000
=0.0323 moles Calculation of number of moles of potassium hydroxide. Volume of potassium hydroxide,V 29.9mL. Molarity of potassium hydroxide solution, Molarity 0.664 M. The number of moles can be calculated by the equation as follows: No of moles=Molarityxmolar massxvolume
1000 No of moles of KOH=Molarity of KOHxvolume of KOH in mL
1000
0.579 Mx 29.9 mL
1000
0.0173moles

The volume and the molarity of nitric acid are known. Then, the number of moles of nitric acid can be calculated using the formula. No of moles=Molarityxvolume in ml
1000 On proper substitution of the values, the number of moles of nitric acid is calculated to be. Similarly, the number of moles of potassium hydroxide is calculated as.

Step 5 of 5

The difference in the number of moles of nitric acid and potassium hydroxide is given below: nHNOnKo0.0323 moles-0.0173 moles
-0.015 moles Each mole ofHNOproduces one moleH*ion and each mole of КОНproduces one of ОНions. Therefore, the number of moles of HNOleft is same as the number of moles of ОНions reacted fromCа (Он),. Each mole ofCа (Он),produces two moles of ОНions. Therefore, the number of moles of Cа (Он),required is given below: nC(O=INo, remaining
2
0.015
2
-0.0075moles Thus, the number of moles of Cа (Он),is obtained and hence, the molarity of Cа (Он),solution can be calculated as follows: The molarity of a solution is calculated as shown below: Volume of Ca(OH), solution in mL
0.0075molesx1000
40.9mL
0.1834M

Part 2

The molarity of original calcium hydroxide solution is0.1834 M.


Initially, nitric acid reacts with of calcium hydroxide to result in the acidic solution, which further reacted with potassium hydroxide, to reach the neutral solution. The number of moles of left unreacted after reaction with calcium hydroxide is equal to the number of moles of potassium hydroxide. Thus, from the given volume and molar concentration of potassium hydroxide, the number of moles of nitric acid remaining after the reaction with calcium hydroxide is calculated. Thus, the difference between the initial number of moles of and number of moles of reacted with , provides the number of moles of reacted with the calcium hydroxide. From the stoichiometry of the reaction, it was identified that each mole of calcium hydroxide neutralizes two mole of . From these data, the number of moles of calcium hydroxide is calculated as . Since the volume of the solution is given as , the molarity of the original solution can be calculated as.

Answer

Part 1

When benzene(С,Н.)
6reacts with oxygen, carbon dioxide and water are produced. If 60molesof oxygen reacts: The reaction consumes
8 moles of benzene (C6H6)
48moles of carbon dioxide and
The reaction produces
24 moles ofwater

Part 2

The molarity of original calcium hydroxide solution is0.1834 M.

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