The four masses shown in the figure are connected by massless, rigid rods.
See figure here: http://farm3.static.flickr.com/2761/4114364565_f05…
Find the moment of inertia about a diagonal axis that passes through masses B and D.
x-coordinate xcm=5.7 cm; y-coordinate ycm=5.7cm
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I = m*r^2 for point masses. So you need the distance of points A & C from the diagonal which is 7.07cm. So I = (.100kg)*(.0707m)^2 + (.200kg)*(.0707m)^2 = 0.00150 kg-m^2
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